Calculate the mass of 2.5 mol of barium hydroxide. How many ions of each type will this portion of alkali contain?

Solution:
m (Ba (OH) ₂) = 2500 mol * 174 g / mol = 427500 g = 427.5 kg
n (Ba⁺2) = 2500 * 1 = 2500 mol
n (OH⁻) = 2500 * 2 = 5000 mol.
Answer: 427.5 kg, 2500 mol and 5000 mol.



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