Calculate the mass of 5% nitric acid solution required to react with 10.6 sodium carbanate.

1. Let’s compose the equality of chemical interaction:

Na2CO3 + 2HNO3 = 2NaNO3 + CO2 + H2O.

2. Calculate the number of moles of sodium carbonate:

n (Na2CO3) = m (Na2CO3) / M (Na2CO3) = 10.6 g / 106 g / mol = 0.1 mol.

3. Using the equality of the chemical interaction, we find the number of moles, and at the end the mass of nitric acid:

n (HNO3) = n (Na2CO3) * 2 = 0.1 mol * 2 = 0.2 mol.

m (HNO3) = n (HNO3) * M (HNO3) = 0.2 mol * 63 g / mol = 12.6 g.

4. Find the mass of the nitric acid solution:

m (solution) = m (HNO3) * 100% / ω (HNO3) = 12.6 g * 100% / 5% = 252 g.

Result: m (solution) = 252 g.