Calculate the mass of 60% acetic acid used to neutralize 120 g of 25% sodium hydroxide solution.

univerkov | August 7, 2021 | education

First, you need to write down the reaction equations.

CH3COOH + NaOH = CH3COONa + H2O.

First, determine the mass of acetic acid.

m = 120 * 0.25 = 30 g.

Next, we determine the molar mass of acetic acid and sodium hydroxide.

M (CH3COOH) = 12 * 2 + 4 + 32 = 60 g / mol.

M (NaOH) = 23 + 16 + 1 = 40 g / mol.

Further, according to the reaction equation, we determine the mass of acetic acid.

X g CH3COOH – 30 g NaOH.

60 g / mol CH3COOH – 40 g / mol NaOH.

X = 60 * 30/40 = 45 g / mol.

Next, we determine the mass of the acetic acid solution.

m (CH3COOH) = 45 / 0.6 = 75 g.

Answer: 75 g.

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