Calculate the mass of a 10% sulfuric acid solution to be added to 200 g of a 60%

| September 11, 2021 | education

Calculate the mass of a 10% sulfuric acid solution to be added to 200 g of a 60% sulfuric acid solution to obtain a 20% sulfuric acid solution.

Data: ω (Н2SO4) 1 – mass fraction of acid in the added solution (ω (Н2SO4) 1 = 10% = 0.1); mр2 is the mass of the initial solution (mр2 = 200 g); ω (H2SO4) 2 – mass fraction of acid in the initial solution (ω (H2SO4) 2 = 60% = 0.6); ωН2SO4 – required mass fraction of acid (ωН2SO4 = 20% = 0.2).

1) The mass of acid in the original solution: m (H2SO4) 2 = ω (H2SO4) 2 * mр2 = 0.6 * 200 = 120 g.

2) The mass of acid in the final solution: mH2SO4 = m (H2SO4) 1 + m (H2SO4) 2 = 0.1mp1 + 120.

3) The mass of the final solution: mр = mр1 + mр2 = mр1 + 200.

4) Mass fraction of acid in the final solution: ωН2SO4 = mН2SO4 / mр = (0.1mр1 + 120) / (mр1 + 200) = 0.2.

5) Weight of the added solution:

0.2 * (mp1 + 200) = 0.1mp1 + 120.

0.2mр1 + 40 = 0.1mр1 + 120.

0.2mp1 – 0.1mp1 = 120 – 40.

0.1mр1 = 80.

mр1 = 80 / 0.1 = 800 g.

Answer: It is necessary to add 800 g of 10% sulfuric acid solution.



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