Calculate the mass of a substance that is formed by the interaction of 39 grams of potassium with sulfur.
1.Calculate the amount of potassium substance according to the formula:
n = m: M, where M is molar mass.
M (K) = 39 g / mol.
n = 39: 39 g / mol = 1 mol.
2. Let’s compose the equation of the reaction between potassium and sulfur:
2K + S = K2S.
According to the reaction equation, for 2 mol of potassium there is 1 mol of potassium sulfide, that is, the substances are in quantitative ratios of 2: 1, which means that the amount of potassium sulfide substance will be 2 times less than the amount of potassium sulfide.
n (K2S) = 1: 2 = 0.5 mol.
Or:
2 mol K – 1 mol K2S.
1 mol Al – n mol K2S.
n mol = (1 mol × 1 mol): 2 = 0.5 mol.
3. Calculate the mass of potassium sulfide by the formula: m = n M,
M (K2S) = 39 × 2 + 32 = 110 g / mol.
m = 110 g / mol × 0.5 mol = 55 g.
Answer: m = 55 g.