Calculate the mass of a sulfuric acid solution with a mass fraction of 0.23, which is necessary to completely neutralize

| April 14, 2021 | education

Calculate the mass of a sulfuric acid solution with a mass fraction of 0.23, which is necessary to completely neutralize a potassium hydroxide solution with a mass of 134.4 g with a mass fraction of alkali of 10%

Reaction: 2KOH + H2SO4 = K2SO4 + 2H2O
It is necessary to find the mass of the potassium hydroxide substance contained in the solution: mv-va = w * mr-pa = 0.1 * 134.4 g = 13.44 g. Now we will find the amount of the hydroxide substance: n = m / M = 13.44 g / 56 g / mol = 0.24 mol. By reaction with 2 mol of hydroxide, 1 mol of sulfuric acid reacts, 0.24 / 2 = n (H2SO4) / 1. n (H2SO4) = 0.12 mol. Let us find the mass of the sulfuric acid substance: m = n * M = 0.12 mol * 98 g / mol = 11.76 g. Let us find the mass of the solution: mr-pa = mv-va / w = 11.76 g / 0.23 = 51.13 g



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