Calculate the mass of a sulfuric acid solution with a mass fraction of H2SO4 10%

Calculate the mass of a sulfuric acid solution with a mass fraction of H2SO4 10%, required to obtain hydrogen with a volume of 8.96 liters by the zinc reaction.

1. The interaction of sulfuric acid with zinc occurs according to the equation:

H2SO4 + Zn = ZnSO4 + H2 ↑.

2. Calculate the chemical amount of released hydrogen:

n (H2) = V (H2): Vm = 8.96: 22.4 = 0.4 mol.

3. Determine the amount of sulfuric acid reacted:

n (H2SO4) = n (H2) = 0.4 mol.

4. Find the mass of the acid:

m (H2SO4) = n (H2SO4) * M (H2SO4);

M (H2SO4) = 2 + 32 + 4 * 16 = 98 g / mol;

m (H2SO4) = 0.4 * 98 = 39.2 g.

5. Let’s calculate the mass of the sulfuric acid solution:

mр-pa (H2SO4) = m (H2SO4): w (H2SO4) = 39.2: 0.1 = 392 g.

Answer: 392