# Calculate the mass of acetaldehyde, which was oxidized with an ammonia solution of silver oxide, if 64 g

**Calculate the mass of acetaldehyde, which was oxidized with an ammonia solution of silver oxide, if 64 g of acetic acid were obtained, which amounted to 0.8 mass fractions of the theoretically possible.**

To solve the problem, we compose the equation:

СН3СОН + Ag2O = CH3COOH + 2Ag – oxidation reaction of acetaldehyde, obtained acetic acid, silver;

Let’s make the calculations:

M (CH3COH) = 44 g / mol;

M (CH3COOH) = 60 g / mol.

Let us determine the theoretical mass of acetic acid if the product yield is known:

W = m (practical) / m (theoretical) * 100;

m (theoretical) = 64 / 0.80 = 80 g.

Find the number of moles of acetic acid:

Y (CH3COOH) = m / M = 80/60 = 1.3 mol.

According to the equation, the amount of moles of aldehyde and organic acid is 1 mole, which means that Y (CH3COH) = 1.3 mole.

Let’s calculate the mass of the aldehyde:

m (CH3COH) = Y * M = 1.3 * 44 = 57.2 g.

Answer: the mass of ethanal is 57.2 g.