Calculate the mass of acetic acid required to neutralize potassium hydroxide with a chemical amount of 0.4 mol

Given:
n (KOH) = 0.4 mol

Find:
m (CH3COOH) -?

1) CH3COOH + KOH => CH3COOK + H2O;
2) n (CH3COOH) = n (KOH) = 0.4 mol;
3) m (CH3COOH) = n * M = 0.4 * 60 = 24 g.

Answer: The mass of CH3COOH is 24 g.



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