Calculate the mass of acetic acid that can react with a 200 g sodium hydroxide solution with a mass fraction of NaOH of 10%

Reaction equation: CH3COOH + NaOH = CH3COONa + H2O
Let’s find the mass of the sodium hydroxide substance m in-va = w * m solution = 0.1 * 200 g = 20 g. Let’s find the amount of the hydroxide substance n = m / M = 20 g / 40 g / mol = 0.5 mol. By reaction with 1 mol of acetic acid, 1 mol of sodium hydroxide reacts, which means n (CH3COOH) = n (NaOH) = 0.5 mol. The mass of acetic acid is m = n * M = 0.5 mol * 60 g / mol = 30 g (M is the molar mass, determined by the periodic table).
Answer: the mass of acetic acid is 30 g.