Calculate the mass of acetic acid used to neutralize 120 g of 25% sodium hydroxide solution.

univerkov | December 9, 2020 | education

CH3-COOH + NaOH —> CH3-COONa + H2O m (NaOH) = 120g * 0.25 = 30g n (NaOH) = 30g / 40g / mol = 0.75mol
In the equation, the ratio is 1: 1 —> n (NaOH) = n (CH3COOH) = 0.75mol m (CH3COOH) = 0.75mol * 60g / mol = 45g
Answer: 45g.

One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.