Calculate the mass of acetylene that will result from the dehydrogenation of ethylene with a volume of 224 liters.

The term dehydrogenation means the removal of hydrogen. The dehydrogenation of ethylene produces acetylene. The reaction takes place at high temperature and in the presence of a catalyst.

CH2 = CH2 -> CH≡CH + H2

As can be seen from the reaction equation, the amount of the starting substance and the amount of the substance of each product are equal. This means (according to Avogadro’s law) and the volumes of all gases under normal conditions will be the same.

V (C2H4) = V (C2H2) = 224 L

The molar mass of acetylene is 26 g / mol. Knowing the molar mass of a gas and its volume, it is easy to find the mass through the amount of substance.

m = n * M, where m is the mass, n is the amount of substance, M is the molar mass

n = V / Vm, where V is the gas volume, Vm is the molar volume.

Molar volume at normal level is equal to 22.4 l / mol.

n = 224 / 22.4 = 10 mol

m = 10 * 26 = 260 g

Answer: 260 g of acetylene.



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