Calculate the mass of alcohol obtained by hydrating 70 g of ethylene if the practical alcohol yield is 94%.

| September 6, 2021 | education

Hydration of an unsaturated hydrocarbon is the process of attaching a water molecule to form a new substance. As a rule, these are alcohols. Ethylene hydration can be written by the following reaction equation:

CH2 = CH2 + H2O = CH3-CH2OH

The product of the ethylene hydration reaction is the monohydric alcohol ethanol (ethyl alcohol).

Molar masses of substances:

M (C2H4) = 28 g / mol;

M (C2H5OH) = 46 g / mol.

Let’s make a proportion according to the reaction equation:

70 g of ethylene corresponds to X g of ethanol, as

28 g / mol of ethylene corresponds to 46 g / mol of ethanol.

X = (70 * 46) / 28 = 115 g ethanol – theoretical yield

Let’s calculate the practical yield of alcohol:

m (C2H5OH) = 115 * 94/100 = 108.1 g

Answer: the mass of ethyl alcohol is 108.1 g.



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