Calculate the mass of aluminum and the mass of oxygen that will be required to obtain aluminum

Calculate the mass of aluminum and the mass of oxygen that will be required to obtain aluminum oxide with a mass of 25.5 g.

1. Aluminum oxide is obtained as a result of the reaction:

4Al + 3O2 = 2Al2O3.

2. Calculate the chemical amount of aluminum oxide:

n (Al2O3) = m (Al2O3): M (Al2O3);

M (Al2O3) = 2 * 27 + 3 * 16 = 102 g / mol;

n (Al2O3) = 25.5: 102 = 0.25 mol.

3. Set the amount of aluminum:

n (Al) = n (Al2O3) * 2 = 0.25 * 2 = 0.5 mol.

4. Determine the amount of oxygen:

n (O2) = n (Al2O3) * 3: 2 = 0.25 * 3: 2 = 0.375 mol.

5. Let’s calculate the mass of aluminum:

m (Al) = n (Al) * M (Al) = 0.5 * 27 = 13.5 g.

6. Find the mass of oxygen:

m (O2) = n (O2) * M (O2) = 0.375 * 32 = 12 g.

Answer: 13.5 g Al, 12 g O2.