Calculate the mass of aluminum bromide that is formed by the interaction of aluminum weighing 5.4 g
April 12, 2021 | education
| Calculate the mass of aluminum bromide that is formed by the interaction of aluminum weighing 5.4 g with an excess of bromine.
Given:
m (Al) = 5.4 g
To find:
m (AlBr3) -?
Decision:
2Al + 3Br2 = 2AlBr3, – we solve the problem, relying on the composed reaction equation:
1) Find the amount of aluminum that has reacted:
n (Al) = m: M = 5.4 g: 27 g / mol = 0.2 mol
2) We compose a logical expression:
If 2 mol of Al gives 2 mol of AlBr3,
then 0.2 mol of Al will give x mol of AlBr3,
then x = 0.2 mol.
3) Find the mass of aluminum bromide formed during the reaction:
m (AlBr3) = n * M = 0.2 mol * 267 g / mol = 53.4 g.
Answer: m (AlBr3) = 53.4 g.
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