Calculate the mass of aluminum chloride formed by the interaction of 81g. aluminum with hydrochloric acid

Calculate the mass of aluminum chloride formed by the interaction of 81g. aluminum with hydrochloric acid, if the yield of the reaction product from the theoretically possible is 80%.

1. Let’s compose the equation of the chemical reaction:

2Al + 6HCl = 2AlCl3 + 3H2.

2. Find the chemical amount of reacted aluminum:

n (Al) = m (Al) / M (Al) = 81 g / 27 g / mol = 3 mol.

3. According to the reaction equation, we find the theoretical chemical amount of aluminum chloride, and at the end its mass:

ntheor (AlCl3) = n (Al) = 3 mol.

nprak (AlCl3) = ntheor (AlCl3) * η (AlCl3) / 100% = 3 mol * 80% / 100% = 2.4 mol.

m (AlCl3) = nprak (AlCl3) * M (AlCl3) = 2.4 mol * 133.5 g / mol = 320.4 g.

Answer: m (AlCl3) = 320.4 g.