Calculate the mass of aluminum chloride formed by the interaction of aluminum with 500

Calculate the mass of aluminum chloride formed by the interaction of aluminum with 500 g of 80% hydrochloric acid solution.

1. Let’s compose the equality of chemical interaction:

2Al + 6HCl = 2AlCl3 + 3H2.

2. Calculate the chemical number of the reacted hydrochloric acid:

m (HCl) = m (solution) * ω (HCl) / 100% = 500 g * 80% / 100% = 400 g.

n (HCl) = m (HCl) / M (HCl) = 400 g / 36.5 g / mol = 10.96 mol.

3. Using the equality of chemical interaction, we calculate the number of moles and, as a result, the mass of aluminum chloride:

n (AlCl3) = n (HCl) / 3 = 10.96 mol / 3 = 3.65 mol.

m (AlCl3) = n (AlCl3) * M (AlCl3) = 3.65 mol * 133.5 g / mol = 487.67 g.

Result: m (AlCl3) = 487.67 g.