The reaction of aluminum with oxygen proceeds according to the following chemical formula:
4Al + 3O2 = 2Al2O3;
From two moles of aluminum, one mole of aluminum oxide is formed.
Let’s find the amount of a substance contained in 135 grams of aluminum:
N Al = 135/27 = 5 mol;
The amount of aluminum oxide substance will be:
N Al2O3 = N Al / 2 = 5/2 = 2.5 mol;
Let’s find the mass of this amount of aluminum oxide:
M Al2O3 = 27 x 2 + 16 x 3 = 102 grams / mol;
m Al2O3 = 2.5 x 102 = 255 grams;
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