Calculate the mass of aluminum reacting with oxygen in the amount of 6 mol Al + O2- Al2O3.

Reaction: 4Al + 3O2 = 2Al2O3
According to the reaction equation, 3 mol of oxygen reacts with 4 mol of aluminum, according to the condition 6 mol of oxygen, we will make the proportion, n (Al) / 4 = 6 mol / 3. Hence n (Al) = 4 * 6/3 = 8 mol.
Let’s find the mass of aluminum: m = n * M, where M = 27 g / mol (molar mass of aluminum, found from the periodic table). m (Al) = 8 mol * 27 g / mol = 216 g.
Answer: the mass of aluminum is 216 g.