Calculate the mass of aluminum required to obtain aluminum oxide Al2O3, the amount of substance 8 mol.

First, let’s write the reaction equation for producing aluminum oxide (Al2O3)
4Al + 3O2 = 2Al2O3
Based on this equation, we see that the amount of the aluminum substance is 2 times the amount of the aluminum oxide substance.
n (Al2O3) = 1 / 2n (Al)
n (Al) = 2 * 8 mol = 16 mol
Using the Periodic Table, we find the molecular weight of aluminum
Mr (Al) = 27
Molecular weight is equal to molar weight
M (Al) = 27 g / mol
Knowing the amount of aluminum substance and its molar mass, we find the mass of the substance
m (Al) = 16 mol * 27 g / mol = 432 g
Answer: m (Al) = 432 g