Calculate the mass of aluminum sulfate formed by the interaction of 23.4 g of aluminum hydroxide with sulfuric acid.

Reaction equation: 2Al (OH) 3 + 3H2SO4 = Al2 (SO4) 3 + 6H2O
Let us find the amount of aluminum hydroxide substance n = m / M = 23.4 g / 78 g / mol = 0.3 mol.
According to the reaction, 1 mol of aluminum sulfate is formed from 2 mol of hydroxide, then 0.3 / 2 = n (aluminum sulfate) / 1. Then the amount of aluminum sulfate substance is n = 0.3 / 2 = 0.15 mol.
Then the mass of sulfate m = n * M = 0.15 mol * 342 g / mol = 51.3 g (M is the molar mass, determined by the periodic table).
Answer: the mass of aluminum sulfate is 51.3 g.