Calculate the mass of aluminum sulfide that will result from the interaction of 5.4 g of aluminum with sulfur.

Let’s find the amount of aluminum substance by the formula:

n = m: M.

M (Al) = 27 g / mol.

n = 5.4 g: 27 g / mol = 0.2 mol.

Let’s compose the reaction equation, find the quantitative ratios of substances.

2Al + 3S = Al2S3.

According to the reaction equation, there is 1 mol of Al2S3 per 2 mol of Al. Substances are in quantitative ratios of 2: 1.

The amount of substance Al2S3 will be 2 times less than Al.

n (Al2S3) = ½ n (Al) = 0.2: 2 = 0.1 mol.

Let’s find the mass of Al2S3.

M (Al2S3) = 150 g / mol.

m = n × M.

m = 150 g / mol × 0.1 mol = 15 g.

Answer: 15 g.