Calculate the mass of aluminum sulfide, which is formed by the interaction of 2.7 mol of aluminum with 3.6 g of sulfur.

| February 6, 2021 | education

Let’s find the amount of aluminum substance by the formula:

n = m: M.

M (Al) = 27 g / mol.

n = 2.7 g: 27 g / mol = 0.1 mol.

Let’s find the amount of sulfur substance:

M (S) = 32 g / mol.

n = 3.6 g: 32 g / mol = 0.11 mol.

Sulfur is in short supply, aluminum in abundance. Solving the sulfur problem.

Let’s compose the reaction equation, find the quantitative ratios of substances.

2Al + 3S = Al2S3.

According to the reaction equation, 3 mol of sulfur accounts for 1 mol of aluminum sulfide. The substances are in quantitative ratios of 3: 1.

The amount of Al2S3 substance will be 3 times less than alcohol.

n (Al2S3) = 1 / 3n (S) = 0.11: 3 = 0.037 mol.

Let’s find the mass of Al2S3.

M (Al2S3.) = 150 g / mol.

m = n × M.

m = 150 g / mol × 0.037 mol = 5.55 g.

Answer: 5.55 g.



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.