Calculate the mass of aluminum that can react with 480 g of 10% copper sulfate (ll) solution.

Given:

m (CuSO4) = 480 g

w% (CuSO4) = 10%

To find:

m (Al) -?

Decision:

1) We compose the reaction equation corresponding to the condition of the problem:

2Al + 3CuSO4 = Al2 (SO4) 3 + 3Cu;

2) Find the mass of copper sulfate in solution:

m (CuSO4) = 480 g * 0.1 = 48 g;

3) Find the amount of copper sulfate:

n (CuSO4) = m: M = 48 g: 160 g / mol = 0.3 mol;

4) We compose logical equality:

if 3 mol CuSO4 requires 2 mol Al,

then 0.3 mol CuSO4 will require x mol Al,

then x = 0.2 mol.

5) Find the mass of aluminum that has reacted:

m (Al) = n * M = 0.2 mol * 27 g / mol = 5.4 g.

Answer: m (Al) = 5.4 g.