Calculate the mass of aluminum that has reacted with sulfur if 60 g of aluminum sulfide is formed.

Let’s write down the solution:
1. In accordance with the condition, we compose the equation:
2Al + 3S = Al2S3 – compounds occur when heated, iron sulfide is obtained;
2. We make calculations of molar masses:
M (Al) = 26.9 g / mol;
M (Al2S3) = 149.8 g / mol.
3. Determine the amount of the product, if the mass is known:
Y (Al2S3) = m / M = 60 / 149.8 = 0.4 mol.
4. Proportion:
X mol (Al) – 0.4 mol (Al2S3);
-2 mol – 1 mol from here, X mol (Al) = 2 * 0.4 / 1 = 0.8 mol.
5. Find the mass of the metal:
m (Al) = Y * M = 0.8 * 26.9 = 21.52 g.
Answer: to carry out the process, aluminum with a mass of 21.52 g is required.