Calculate the mass of ammonia that can be obtained from nitrogen with a volume of 448 liters

Calculate the mass of ammonia that can be obtained from nitrogen with a volume of 448 liters, if the yield of the reaction product from the theoretically possible is 62.5%

N2 + 3H2 = 2NH3

Let’s calculate the chemical amount of nitrogen: n = V / Vm, where Vm = 22.4 dm ^ 3 * mol ^ (- 1)

n (N2) = 448 / 22.4 = 20 mol.

Let us write out the chemical quantities and coefficients from the reaction equation for N2 and NH3

20 mol – x mol, therefore n (NH3) = 20 * 2/1 = 40 mol

1 mol – 2 mol

Let’s calculate the theoretical mass of ammonia: m = n * M

m (NH3) = 40 * (14 + 3 * 1) = 680 gr.

Let’s calculate the practical mass of ammonia, based on the yield of the reaction product: n = m (practical) / m (theoretical), therefore m (practical) = n * m (theory)

m (practical) (NH3) = 0.625 * 680 = 425 gr.