Calculate the mass of ammonium chloride required to produce 2.24 liters of ammonia.

Let’s find the chemical amount of ammonia. For this purpose, we divide its volume by the standard volume of 1 mole of gas (filling 22.40 liters)
N NH3 = 2.24 / 22.4 = 0.1 mol;
To get 0.1 mol of ammonia, you need to take 0.1 mol of ammonium chloride.
Let’s determine its weight.
To do this, multiply the chemical (molar) amount of a substance by its molar (atomic) mass.
M NH4Cl = 14 + 4 + 35.5 = 53.5 grams / mol;
The weight of ammonium chloride will be:
m NH4 Cl = 0.1 x 53.5 = 5.35 grams.