Calculate the mass of ammonium chloride that is formed by the interaction of 6.72 liters of ammonia with hydrogen chloride.

To solve the problem, we write down data on the condition of the problem:
NH3 + HCl = NH4Cl – compounds, ammonium chloride was formed;
Calculations by formulas:
M (NH3) = 17 g / mol;
M (NH4Cl) = 53.5 g / mol.
Proportion:
1 mol of gas at normal level – 22.4 l
X mol (NH3) – 6.72 L from here, X mol (NH3) = 1 * 6.72 / 22.4 = 0.3 mol.
Y (NH4Cl) = 0.3 mol since the amount of substances is 1 mol.
Find the mass of salt:
m (NH4Cl) = Y * M = 0.3 * 53.5 = 16.05 g
Answer: received ammonium chloride weighing 16.05 g