Calculate the mass of ammonium chloride, which is formed by the interaction of hydrogen chloride with a mass of 7.3 g

Calculate the mass of ammonium chloride, which is formed by the interaction of hydrogen chloride with a mass of 7.3 g with ammonia with a mass of 5.1 g.

The reaction of ammonia with hydrogen chloride is described by the following chemical reaction equation:

NH3 + HCl = NH4Cl;

When one mole of ammonia reacts with one mole of hydrochloric acid, one mole of ammonium chloride is formed.

Let’s find the available quantities of the substance.

M NH3 = 14 + 3 = 17 grams / mol;

N NH3 = 5.1 / 17 = 0.3 mol;

M HCl = 1 + 35.5 = 36.5 grams / mol;

N HCl = 7.3 / 36.5 = 0.2 mol;

When 0.2 mol of ammonia reacts with 0.2 mol of hydrochloric acid, 0.2 mol of ammonium chloride is formed.

M NH4Cl = 53.5 grams / mol;

m NH4Cl = 0.2 x 53.5 = 10.7 grams;