Calculate the mass of ammonium chloride, which is formed by the interaction of hydrogen

Calculate the mass of ammonium chloride, which is formed by the interaction of hydrogen chloride with a volume of 4.48 liters with 5.1 g of ammonia.

Ammonia reacts with hydrochloric acid in equal molar amounts. In this case, the same amount of ammonium chloride salt is synthesized.

This reaction proceeds according to the following chemical reaction equation:

NH3 + HCl = NH4Cl;

Let’s determine the chemical amount of ammonia.

M NH3 = 14 + 3 = 17 grams / mol; N NH3 = 5.1 / 17 = 0.3 mol;

Let’s calculate the chemical amount of hydrochloric acid. For this purpose, we divide its volume by the standard volume of 1 mole of gas (constituting 22.40 liters)

N HCl = 4.48 / 22.4 = 0.2 mol;

0.2 mol of ammonia will combine with 0.2 mol of hydrochloric acid. This will synthesize 0.2 mol of ammonium chloride.

Let’s calculate its weight. To do this, we multiply the chemical (molar) amount of a substance by its molar (atomic) mass.

M NH4Cl = 14 + 4 + 35.5 = 53.5 grams / mol;

The weight of ammonium chloride will be:

m NH4 Cl = 0.2 x 53.5 = 10.7 grams;