Calculate the mass of barium chloride, which was spent on the reaction with sulfuric acid

Calculate the mass of barium chloride, which was spent on the reaction with sulfuric acid, if the mass of the precipitate was 106 grams.

Barium chloride reacts with sulfuric acid. At the same time, a water-insoluble barium sulfate salt is synthesized, which precipitates. The reaction is described by the following chemical reaction equation.

BaCl2 + H2SO4 = BaSO4 + 2HCl;

Barium chloride reacts with sulfuric acid in equal molar amounts. This produces the same amount of insoluble barium sulfate.

Let’s calculate the chemical amount of barium sulfate.

M BaSO4 = 137 + 32 + 16 x 4 = 233 grams / mol; N BaSO4 = 106/233 = 0.455 mol;

Find the weight of this amount of barium chloride.

M BaCl2 = 137 + 35.5 x 2 = 208 grams / mol; m BaCl2 = 0.455 x 208 = 94.64 grams;