Calculate the mass of barium hydroxide Ba (OH) 2 obtained from barium with a mass of 548 g.

From one mole of barium, one mole of its hydroxide can be obtained.

Let’s find the amount of the substance contained in 548 grams of barium.

M Ba = 137 grams / mol;

N Ba = 548/137 = 4 mol;

Let us determine the mass of 4 mol of barium hydroxide.

M Ba (OH) 2 = 137 + (16 + 1) x 2 = 171 g / mol;

m Ba (OH) 2 = 4 x 171 = 684 grams;