Calculate the mass of barium sulfate formed by the interaction of 200 g of 7% sulfuric acid
Calculate the mass of barium sulfate formed by the interaction of 200 g of 7% sulfuric acid solution with a solution of barium chloride containing 2 mol of this salt.
The reaction between sulfuric acid and barium chloride is described by the following chemical reaction equation:
BaCl2 + H2SO4 = BaSO4 + 2HCl;
In the interaction of 1 mol of barium chloride and 1 mol of sulfuric acid, 1 mol of insoluble barium sulfate is synthesized.
Let’s calculate the chemical amount of a substance that is contained in 200 grams of a 7% sulfuric acid solution.
M H2SO4 = 2 + 32 + 16 x 4 = 98 grams / mol;
N H2SO4 = 200 x 0.07 / 98 = 0.143 mol;
The same amount of barium sulfate will be synthesized.
Let’s calculate its weight.
M BaSO4 = 137 + 32 + 16 x 4 = 233 grams / mol;
m BaSO4 = 233 x 0.143 = 33.32 grams;