Calculate the mass of barium sulfate resulting from mixing a solution containing

Calculate the mass of barium sulfate resulting from mixing a solution containing 20.8 g of barium chloride with an excess of magnesium sulfate solution.

The reaction between magnesium sulfate and barium chloride is described by the following chemical reaction equation:

BaCl2 + MgSO4 = BaSO4 + MgCl2;

Upon the interaction of 1 mol of barium chloride and 1 magnesium sulfate, 1 mol of insoluble barium sulfate is synthesized.

Let’s calculate the chemical amount of a substance that is contained in 20.8 grams of barium chloride.

M BaCl2 = 137 + 35.5 x 2 = 208 grams / mol;

N BaCl2 = 20.8 / 208 = 0.1 mol;

The same amount of barium sulfate will be synthesized.

Let’s calculate its weight.

M BaSO4 = 137 + 32 + 16 x 4 = 233 grams / mol;

m BaSO4 = 233 x 0.1 = 23.3 grams;