Calculate the mass of bromine that can be added to a 5.6 liter ethene.

To solve, we write the equation:
Н2С = СН2 + Br2 = H2C – Br – CH2Br (C2H4Br2) – during the addition reaction
Dibromoethane was obtained 1 mol to 1 mol;
Let’s calculate the molar masses of substances:
M (C2H4) = 28 g / mol;
M (Br2) = 159.8 g / mol.
Let’s determine the number of moles of ethylene:
1 mol of gas at normal level – 22.4 liters.
X mol (C2H4) – 5.6 liters. hence, X mol (C2H4) = 1 * 5.6 / 22.4 = 0.25 mol.
According to the equation, the amount of moles of ethylene and bromine are equal to 1 mol, which means that Y (Br2) = 0.25 mol.
Find the mass of bromine:
m (Br2) = Y * M = 0.25 * 159.8 = 39.95 g.
Answer: the mass of bromine is 39.95 g.