Calculate the mass of bromine water (mass fraction of bromine 2.4%) that propylene with a volume

Calculate the mass of bromine water (mass fraction of bromine 2.4%) that propylene with a volume of 1.68 liters can discolor.

C3H6 + Br2 → C3H6Br2

Propylene amount n (C3H6) = V (C3H6): Vm = 1.68 L: 22.4 L / mol = 0.075 mol.

According to the equation, the ratio of the amount of propylene to the amount of bromine is 1: 1. So, n (C3H6): n (Br2) = 1: 1 = 0, 075: 0, 075. That is, the amount of bromine is 0, 075 mol.

The molar mass of bromine M (Br2) = 2 × 80 = 160 g / mol.

Bromine mass m (Br2) = n (Br2) × M (Br2) = 0.075 × 160 = 12 g.

The mass of bromine water is m = 12 g × 100%: 2.4% = 500 g.