Calculate the mass of bromine water that will be required to fully interact with 186 g of 1% aniline solution.

Given:
ω (Br2) = 2%
m solution (C6H5NH2) = 186 g
ω (C6H5NH2) = 1%

To find:
m solution (Br2) -?

Decision:
1) 3Br2 + C6H5NH2 => C6H2Br3NH2 + 3HBr;
2) m (C6H5NH2) = ω * m solution / 100% = 1% * 186/100% = 1.86 g;
3) M (C6H5NH2) = 93 g / mol;
4) n (C6H5NH2) = m / M = 1.86 / 93 = 0.02 mol;
5) n (Br2) = n (C6H5NH2) * 3 = 0.02 * 3 = 0.06 mol;
6) M (Br2) = 160 g / mol;
7) m (Br2) = n * M = 0.06 * 160 = 9.6 g;
8) m solution (Br2) = m * 100% / ω = 9.6 * 100% / 2% = 480 g.

Answer: The mass of bromine water is 480 g.