Calculate the mass of bromine water with a mass fraction of bromine of 2%, which will be required for full interaction with 186 g of a 1% solution of aniline
1. Let’s compose the equation of a chemical reaction.
C6H5NH2 + 3Br2 = C6H2Br3NH2 + 3HBr
2. Find the amount of aniline reacted.
m (C6H5NH2) = m (solution) * ω (C6H5NH2) / 100% = 186 g * 1% / 100% = 1.86 g.
n (C6H5NH2) = m (C6H5NH2) / M (C6H5NH2) = 1.86 g / 93 g / mol = 0.02 mol.
3. Using the reaction equation, we find the amount of bromine and, subsequently, the mass of bromine water.
n (Br2) = n (C6H5NH2) * 3 = 0.02 mol * 3 = 0.06 mol.
m (Br2) = n (Br2) * M (Br2) = 0.06 mol * 160 g / mol = 9.6 g.
m (solution) = m (Br2) * 100% / ω (Br2) = 9.6 g * 100% / 2% = 480 g.
Answer: m (bromine water) = 480 g.
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