Calculate the mass of butane that can be obtained from 540 g of butadiene-1.3

Let’s execute the solution:
1. In accordance with the condition of the problem, we write the equation:
m = 540 g. X g. -?
Н2С = СН – СН = СН2 + 2Н2 = Н3С – СН2 – СН2 = СН3 – hydrogenation, butane was obtained;
1 mol 1 mol.
2. We make calculations:
M (C4H6) = 54 g / mol.
M (C4H10) = 58 g / mol.
3. Let us determine Y of the initial substance, if the mass is known:
Y (C4H6) = m / M 540/54 = 10 mol.
Y (C4H10) = 10 mol since the amount of substances according to the equation is 1 mol.
4. Find the mass of the product:
m (C4H10) = Y * M = 10 * 58 = 580 g.
Answer: 580 g butane was formed.