Calculate the mass of calcium acetate obtained in the interaction of 20g. CH3COOH with CaO.

Let’s write the equation of the process of obtaining calcium acetate:

2СН3СООН + CaO = (CH3COO) 2Ca + H2O – exchange, calcium acetate salt was formed;
Calculations:
M (CH3COOH) = 60 g / mol;

M (calcium acetate) = 158 g / mol;

Y (CH3COOH) = m / M = 20/60 = 0.3 mol.

3. Proportion:

0.3 mol (CH3COOH) – X mol (calcium acetate);

-2 mol – 1 mol from here, X mol (calcium acetate) = 0.3 * 1/2 = 0.15 mol.

Find the mass of the product:
m (calcium acetate) = Y * M = 0.15 * 158 = 23.7 g

Answer: Received calcium acetate weighing 23.7 g