Calculate the mass of calcium carbonate (Ca CO 3) 120 kg of limestone containing 8% impurities.

univerkov | May 3, 2021 | education

Given:
m (limestone) = 120 kg = 120,000 g
ω approx. = 8%

To find:
m (CaCo3) -?

Decision:
1) Calculate the mass fraction of pure CaCO3:
ω (СaCO3) = 100% – ω approx. = 100% – 8% = 92%;
2) Calculate the mass of pure CaCO3:
m (CaCO3) = ω (CaCO3) * m (limestone) / 100% = 92% * 120,000 / 100% = 110400 g.

Answer: The mass of pure CaCO3 is 110400 g.

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