Calculate the mass of calcium hydroxide obtained by quenching calcium oxide weighing 112 kg

| March 20, 2021 | education

Calculate the mass of calcium hydroxide obtained by quenching calcium oxide weighing 112 kg with water. What is the mass and volume of water required for the reaction?

Let’s implement the solution:
1. We write down the equation according to the problem statement:
m = 112 kg; X g -? X l. -?
CaO + H2O = Ca (OH) 2 – compounds, calcium hydroxide is released;
1 mol 1 mol 1 mol.
2. Calculations:
M (CaO) = 56 g / mol;
M (H2O) = 18 g / mol;
M Ca (OH) 2 = 74 g / mol;
m (CaO) = 112000 g.
3. Determine the amount of the original substance:
Y (CaO) = m / M = 112000/56 = 2000 mol;
Y (H2O) = m / M = 2000/18 = 111 mol;
Y Ca (OH) 2 = 111 mol since the amount of these substances is equal according to the equation 1 mol.
4. Find the mass and volume of H2O, the mass of Ca (OH) 2:
m (H2O) = Y / M = 111 * 18 = 1999.9 = 2000 g;
V (H2O) = 111 * 22.4 = 2486.4 L;
m Ca (OH) 2 = Y * M = 111 * 74 = 8214 g.
Answer: to carry out the process, you will need water with a mass of 2000 g, a volume of 2486.4 liters, calcium hydroxide with a mass of 8214 g is obtained.



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