Calculate the mass of calcium oxide and carbon dioxide, which will be obtained

Calculate the mass of calcium oxide and carbon dioxide, which will be obtained by calcining 50 g of chalk, which contains calcium carbonate (95%) and non-decomposing impurities.

Given:

m (CaCO3) = 50 g

w% (CaCO3) = 95%

To find:

m (CaO) -?

m (CO2) -?

Decision:

CaCO3 -> (load) = CO2 + CaO, – we solve the problem based on the composed reaction equation:

1) Find the mass of calcium carbonate that has reacted:

m (CaCO3) = 50 g * 0.95 = 47.5 g

2) Find the amount of calcium carbonate:

n (CaCO3) = m: M = 47.5 g: 100 g / mol = 0.475 mol

3) Find the mass of carbon dioxide by the first logical expression:

if 1 mol of CaCO3 gives 1 mol of CO2,

then 0.475 mole CaCO3 will give x mole CO2,

then x = 0.475 mol.

m (CO2) = n * M = 0.475 mol * 44 g / mol = 20.9 g

4) Find the mass of calcium oxide by the second logical expression:

if 1 mol of CaCO3 gives 1 mol of CaO,

then 0.475 mol of CaCO3 will give x mol of CaO,

then x = 0.475 mol.

m (CaO) = n * M = 0.475 mol * 56 g / mol = 26.6 g.

Answer: m (CO2) = 20.9 g; m (CaO) = 26.6 g.