Calculate the mass of calcium oxide formed during the decomposition of 500 limestone

Calculate the mass of calcium oxide formed during the decomposition of 500 limestone with a mass fraction of impurities of 20%.

The limestone roasting reaction is described by the following equation:

CaCO3 = CaO + CO2 ↑;

When decomposing 1 mol of limestone, 1 mol of calcium oxide and 1 mol of carbon monoxide are obtained.

Find the molar amount of calcium carbonate. For this purpose, we divide its weight by its molar weight.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol; N CaCO3 = 500 x 0.8 / 100 = 4 mol;

Let’s determine the mass of 4 mol of calcium oxide.

To do this, we multiply the amount of the substance by its molar weight.

M CaO = 40 + 16 = 56 grams / mol; m CaO = 4 x 56 = 224 grams;



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.