Calculate the mass of calcium oxide formed when heating limestone weighing 600 g with a mass fraction of CaCO3 80%.

The decomposition reaction of limestone is described by the following chemical reaction equation:

CaCO3 = CaO + CO2;

The decomposition of 1 mol of limestone synthesizes 1 mol of gaseous carbon dioxide.

This also synthesizes 1 mol of calcium oxide

Let’s calculate the available chemical amount of calcium carbonate substance.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;

N CaCO3 = 600 x 0.8 / 100 = 4.8 mol;

During the reaction, 4.8 mol of calcium oxide will be synthesized.

N CaO = 4.8 mol;

Its weight will be:

M CaO = 40 + 16 = 56 grams / mol;

m CaO = 56 x 4.8 = 268.8 grams;