Calculate the mass of calcium oxide obtained from 200 kg of calcium carbonate containing 20% impurities

Calculate the mass of calcium oxide obtained from 200 kg of calcium carbonate containing 20% impurities. The calcium oxide yield is 95%.

The limestone decomposition reaction is described by the following chemical reaction equation:

CaCO3 = CaO + CO2;

The decomposition of 1 mol of limestone synthesizes 1 mol of gaseous carbon dioxide.

Let’s calculate the available chemical amount of calcium carbonate substance.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;

N CaCO3 = 200,000 x 0.8 / 100 = 1,600 mol;

Taking into account the yield of 95% in the course of the reaction, 1,600 x 0.95 = 1,520 mol of calcium oxide will be synthesized.

Let’s calculate the weight of calcium oxide. To do this, we multiply the amount of the substance by its molar weight.

M CaO = 40 + 16 = 56 grams / mol;

m CaO = 56 x 1 520 = 85 120 grams = 85.12 kg;