Calculate the mass of calcium required for the reaction with 365 g of a 30% hydrochloric acid solution.

Calculate the mass of calcium required for the reaction with 365 g of a 30% hydrochloric acid solution. How much hydrogen will be released in this case?

Given:
m solution (HCl) = 365 g
ω (HCl) = 30%

To find:
m (Ca) -?
V (H2) -?

Decision:
1) Ca + 2HCl => CaCl2 + H2;
2) Mr (Ca) = Ar (Ca) = 40 g / mol;
Mr (HCl) = Ar (H) + Ar (Cl) = 1 + 35.5 = 36.5 g / mol;
3) m (HCl) = ω (HCl) * m solution (HCl) / 100% = 30% * 365/100% = 109.5 g;
4) n (HCl) = m (HCl) / Mr (HCl) = 109.5 / 36.5 = 3 mol;
5) n (Ca) = n (HCl) / 2 = 3/2 = 1.5 mol;
6) m (Ca) = n (Ca) * Mr (Ca) = 1.5 * 40 = 60 g;
7) n (H2) = n (HCl) / 2 = 3/2 = 1.5 mol;
8) V (H2) = n (H2) * Vm = 1.5 * 22.4 = 33.6 liters.

Answer: Ca mass is 60 g; volume H2 – 33.6 liters.