Calculate the mass of CaO and the volume of carbon dioxide that can be obtained from 200g of calcium carbonate.

Given:
m (CaCO3) = 200 g
To find:
m (CaO)
V (CO2)
Decision:
CaCO3 = CaO + CO2
n (CaCO3) = m / M = 200 g / 100 g / mol = 2 mol
n (CaCO3): n (CaO) = 1: 1
n (CaO) = 2 mol
n (CaCO3): n (CO2) = 1: 1
n (CO2) = 2 mol
m (CaO) = n * M = 2 mol * 56 g / mol = 112 g
V (CO2) = n * Vm = 2 mol * 22.4 l / mol = 44.8 l
Answer: 112 g; 44.8 l



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