Calculate the mass of carbon dioxide released by the action of a hydrochloric acid solution on 225 g of calcium carbonate?

univerkov | March 9, 2021 | education

The equation of the ongoing reaction: 2HCl + CaCO3 = CaCl2 + H2O + CO2.
1) According to the periodic table, we determine the molar mass of calcium carbonate: 40 + 12 + 48 = 100.
2) Find the amount of carbonate substance. To do this, we divide the mass by the molar mass: 225/100 = 2.25 mol.
3) According to the reaction equation, there is one mole of carbon dioxide per mole of calcium carbonate. This means that the amount of carbon dioxide substance is 2.25 mol.
4) Molar mass of carbon dioxide: 12 + 32 = 44.
5) The mass of carbon dioxide: 2.25 * 44 = 9g – the answer.

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