Calculate the mass of carbon monoxide formed during the calcination of 2 tons of limestone containing

Calculate the mass of carbon monoxide formed during the calcination of 2 tons of limestone containing 12% impurities.

The decomposition reaction of limestone is described by the following chemical reaction equation:

CaCO3 = CaO + CO2;

The decomposition of 1 mol of limestone synthesizes 1 mol of gaseous carbon dioxide.

Let’s calculate the available chemical amount of calcium carbonate substance.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;

N CaCO3 = 2,000,000 x 0.88 / 100 = 17,600 mol;

During the reaction, the same amount of carbon dioxide will be synthesized.

Let’s calculate its weight.

M CO2 = 12 + 16 x 2 = 44 grams / mol;

m CO2 = 44 x 17 600 = 774.4 kg;